Ian, Ken and Tommy had a total of 428 pens at first. After a week, the number of Ian's pens became 4 times the number of pens he had at first. The number of Ken's pens decreased by 142. Tommy had half as many pens as he had at first. In the end, the three boys had the same number of pens.
- How many pens did Tommy have at first?
- What was the total number of pens that the three boys had in the end?
|
Ian |
Ken |
Tommy |
Total |
Before |
1 u |
4 u + 142 |
8 u |
|
Change |
x 4 |
- 142 |
x 12 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of pens at first
=
1 u + 4 u + 142 + 8 u
= 13 u + 142
13 u + 142 = 42813 u = 428 - 14213 u = 286
1 u = 286 ÷ 13 = 22 Number of pens that Tommy had at first
= 4 u ÷
12= 4 u x
21= 8 u = 8 x 22 = 176(b)Total number of pens that the three boys had at the end = 12 u = 12 x 22 = 264 Answer(s): (a) 176; (b) 264