Ivan, Vincent and Jenson had a total of 385 coins at first. After a week, the number of Ivan's coins became 3 times the number of coins he had at first. The number of Vincent's coins decreased by 115. Jenson had half as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Jenson have at first?
- What was the total number of coins that the three boys had in the end?
|
Ivan |
Vincent |
Jenson |
Total |
Before |
1 u |
3 u + 115 |
6 u |
|
Change |
x 3 |
- 115 |
x 12 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of coins at first
=
1 u + 3 u + 115 + 6 u
= 10 u + 115
10 u + 115 = 38510 u = 385 - 11510 u = 270
1 u = 270 ÷ 10 = 27 Number of coins that Jenson had at first
= 3 u ÷
12= 3 u x
21= 6 u = 6 x 27 = 162(b)Total number of coins that the three boys had at the end = 9 u = 9 x 27 = 243 Answer(s): (a) 162; (b) 243