Mark, Sean and Tom had a total of 524 coins at first. After a week, the number of Mark's coins became 4 times the number of coins he had at first. The number of Sean's coins decreased by 355. Tom had half as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Tom have at first?
- What was the total number of coins that the three boys had in the end?
|
Mark |
Sean |
Tom |
Total |
Before |
1 u |
4 u + 355 |
8 u |
|
Change |
x 4 |
- 355 |
x 12 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of coins at first
=
1 u + 4 u + 355 + 8 u
= 13 u + 355
13 u + 355 = 52413 u = 524 - 35513 u = 169
1 u = 169 ÷ 13 = 13 Number of coins that Tom had at first
= 4 u ÷
12= 4 u x
21= 8 u = 8 x 13 = 104(b)Total number of coins that the three boys had at the end = 12 u = 12 x 13 = 156 Answer(s): (a) 104; (b) 156