Billy, Neave and Ahmad had a total of 375 pens at first. After a week, the number of Billy's pens became 4 times the number of pens he had at first. The number of Neave's pens decreased by 144. Ahmad had one-quarter as many pens as he had at first. In the end, the three boys had the same number of pens.
- How many pens did Ahmad have at first?
- What was the total number of pens that the three boys had in the end?
|
Billy |
Neave |
Ahmad |
Total |
Before |
1 u |
4 u + 144 |
16 u |
|
Change |
x 4 |
- 144 |
x 14 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of pens at first
=
1 u + 4 u + 144 + 16 u
= 21 u + 144
21 u + 144 = 37521 u = 375 - 14421 u = 231
1 u = 231 ÷ 21 = 11 Number of pens that Ahmad had at first
= 4 u ÷
14= 4 u x
41= 16 u = 16 x 11 = 176(b)Total number of pens that the three boys had at the end = 12 u = 12 x 11 = 132 Answer(s): (a) 176; (b) 132