Billy, John and Xavier had a total of 437 beads at first. After a week, the number of Billy's beads became 5 times the number of beads he had at first. The number of John's beads decreased by 245. Xavier had half as many beads as he had at first. In the end, the three boys had the same number of beads.
- How many beads did Xavier have at first?
- What was the total number of beads that the three boys had in the end?
|
Billy |
John |
Xavier |
Total |
Before |
1 u |
5 u + 245 |
10 u |
|
Change |
x 5 |
- 245 |
x 12 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of beads at first
=
1 u + 5 u + 245 + 10 u
= 16 u + 245
16 u + 245 = 43716 u = 437 - 24516 u = 192
1 u = 192 ÷ 16 = 12 Number of beads that Xavier had at first
= 5 u ÷
12= 5 u x
21= 10 u = 10 x 12 = 120(b)Total number of beads that the three boys had at the end = 15 u = 15 x 12 = 180 Answer(s): (a) 120; (b) 180