Ian, Howard and Jeremy had a total of 495 pens at first. After a week, the number of Ian's pens became 5 times the number of pens he had at first. The number of Howard's pens decreased by 79. Jeremy had one-quarter as many pens as he had at first. In the end, the three boys had the same number of pens.
- How many pens did Jeremy have at first?
- What was the total number of pens that the three boys had in the end?
|
Ian |
Howard |
Jeremy |
Total |
Before |
1 u |
5 u + 79 |
20 u |
|
Change |
x 5 |
- 79 |
x 14 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of pens at first
=
1 u + 5 u + 79 + 20 u
= 26 u + 79
26 u + 79 = 49526 u = 495 - 7926 u = 416
1 u = 416 ÷ 26 = 16 Number of pens that Jeremy had at first
= 5 u ÷
14= 5 u x
41= 20 u = 20 x 16 = 320(b)Total number of pens that the three boys had at the end = 15 u = 15 x 16 = 240 Answer(s): (a) 320; (b) 240