Reggie, Bryan and Fred had a total of 531 buttons at first. After a week, the number of Reggie's buttons became 3 times the number of buttons he had at first. The number of Bryan's buttons decreased by 355. Fred had one-quarter as many buttons as he had at first. In the end, the three boys had the same number of buttons.
- How many buttons did Fred have at first?
- What was the total number of buttons that the three boys had in the end?
|
Reggie |
Bryan |
Fred |
Total |
Before |
1 u |
3 u + 355 |
12 u |
|
Change |
x 3 |
- 355 |
x 14 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of buttons at first
=
1 u + 3 u + 355 + 12 u
= 16 u + 355
16 u + 355 = 53116 u = 531 - 35516 u = 176
1 u = 176 ÷ 16 = 11 Number of buttons that Fred had at first
= 3 u ÷
14= 3 u x
41= 12 u = 12 x 11 = 132(b)Total number of buttons that the three boys had at the end = 9 u = 9 x 11 = 99 Answer(s): (a) 132; (b) 99