Seth, Riordan and Elijah had a total of 556 coins at first. After a week, the number of Seth's coins became 5 times the number of coins he had at first. The number of Riordan's coins decreased by 218. Elijah had one-quarter as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Elijah have at first?
- What was the total number of coins that the three boys had in the end?
|
Seth |
Riordan |
Elijah |
Total |
Before |
1 u |
5 u + 218 |
20 u |
|
Change |
x 5 |
- 218 |
x 14 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of coins at first
=
1 u + 5 u + 218 + 20 u
= 26 u + 218
26 u + 218 = 55626 u = 556 - 21826 u = 338
1 u = 338 ÷ 26 = 13 Number of coins that Elijah had at first
= 5 u ÷
14= 5 u x
41= 20 u = 20 x 13 = 260(b)Total number of coins that the three boys had at the end = 15 u = 15 x 13 = 195 Answer(s): (a) 260; (b) 195