Luis, Simon and Jenson had a total of 590 beads at first. After a week, the number of Luis's beads became 5 times the number of beads he had at first. The number of Simon's beads decreased by 200. Jenson had one-quarter as many beads as he had at first. In the end, the three boys had the same number of beads.
- How many beads did Jenson have at first?
- What was the total number of beads that the three boys had in the end?
|
Luis |
Simon |
Jenson |
Total |
Before |
1 u |
5 u + 200 |
20 u |
|
Change |
x 5 |
- 200 |
x 14 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of beads at first
=
1 u + 5 u + 200 + 20 u
= 26 u + 200
26 u + 200 = 59026 u = 590 - 20026 u = 390
1 u = 390 ÷ 26 = 15 Number of beads that Jenson had at first
= 5 u ÷
14= 5 u x
41= 20 u = 20 x 15 = 300(b)Total number of beads that the three boys had at the end = 15 u = 15 x 15 = 225 Answer(s): (a) 300; (b) 225