Henry, Xavier and Pierre had a total of 592 pens at first. After a week, the number of Henry's pens became 5 times the number of pens he had at first. The number of Xavier's pens decreased by 304. Pierre had half as many pens as he had at first. In the end, the three boys had the same number of pens.
- How many pens did Pierre have at first?
- What was the total number of pens that the three boys had in the end?
|
Henry |
Xavier |
Pierre |
Total |
Before |
1 u |
5 u + 304 |
10 u |
|
Change |
x 5 |
- 304 |
x 12 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of pens at first
=
1 u + 5 u + 304 + 10 u
= 16 u + 304
16 u + 304 = 59216 u = 592 - 30416 u = 288
1 u = 288 ÷ 16 = 18 Number of pens that Pierre had at first
= 5 u ÷
12= 5 u x
21= 10 u = 10 x 18 = 180(b)Total number of pens that the three boys had at the end = 15 u = 15 x 18 = 270 Answer(s): (a) 180; (b) 270