Mark, Cody and Oscar had a total of 544 coins at first. After a week, the number of Mark's coins became 3 times the number of coins he had at first. The number of Cody's coins decreased by 384. Oscar had half as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Oscar have at first?
- What was the total number of coins that the three boys had in the end?
|
Mark |
Cody |
Oscar |
Total |
Before |
1 u |
3 u + 384 |
6 u |
|
Change |
x 3 |
- 384 |
x 12 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of coins at first
=
1 u + 3 u + 384 + 6 u
= 10 u + 384
10 u + 384 = 54410 u = 544 - 38410 u = 160
1 u = 160 ÷ 10 = 16 Number of coins that Oscar had at first
= 3 u ÷
12= 3 u x
21= 6 u = 6 x 16 = 96(b)Total number of coins that the three boys had at the end = 9 u = 9 x 16 = 144 Answer(s): (a) 96; (b) 144