Ian, Vincent and Oliver had a total of 502 coins at first. After a week, the number of Ian's coins became 5 times the number of coins he had at first. The number of Vincent's coins decreased by 294. Oliver had half as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Oliver have at first?
- What was the total number of coins that the three boys had in the end?
|
Ian |
Vincent |
Oliver |
Total |
Before |
1 u |
5 u + 294 |
10 u |
|
Change |
x 5 |
- 294 |
x 12 |
|
After |
5 u |
5 u |
5 u |
15 u |
(a)
Total number of coins at first
=
1 u + 5 u + 294 + 10 u
= 16 u + 294
16 u + 294 = 50216 u = 502 - 29416 u = 208
1 u = 208 ÷ 16 = 13 Number of coins that Oliver had at first
= 5 u ÷
12= 5 u x
21= 10 u = 10 x 13 = 130(b)Total number of coins that the three boys had at the end = 15 u = 15 x 13 = 195 Answer(s): (a) 130; (b) 195