Oscar, Jeremy and Cole had a total of 385 buttons at first. After a week, the number of Oscar's buttons became 3 times the number of buttons he had at first. The number of Jeremy's buttons decreased by 225. Cole had half as many buttons as he had at first. In the end, the three boys had the same number of buttons.
- How many buttons did Cole have at first?
- What was the total number of buttons that the three boys had in the end?
|
Oscar |
Jeremy |
Cole |
Total |
Before |
1 u |
3 u + 225 |
6 u |
|
Change |
x 3 |
- 225 |
x 12 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of buttons at first
=
1 u + 3 u + 225 + 6 u
= 10 u + 225
10 u + 225 = 38510 u = 385 - 22510 u = 160
1 u = 160 ÷ 10 = 16 Number of buttons that Cole had at first
= 3 u ÷
12= 3 u x
21= 6 u = 6 x 16 = 96(b)Total number of buttons that the three boys had at the end = 9 u = 9 x 16 = 144 Answer(s): (a) 96; (b) 144