Luis, Brandon and Fabian had a total of 479 coins at first. After a week, the number of Luis's coins became 3 times the number of coins he had at first. The number of Brandon's coins decreased by 259. Fabian had half as many coins as he had at first. In the end, the three boys had the same number of coins.
- How many coins did Fabian have at first?
- What was the total number of coins that the three boys had in the end?
|
Luis |
Brandon |
Fabian |
Total |
Before |
1 u |
3 u + 259 |
6 u |
|
Change |
x 3 |
- 259 |
x 12 |
|
After |
3 u |
3 u |
3 u |
9 u |
(a)
Total number of coins at first
=
1 u + 3 u + 259 + 6 u
= 10 u + 259
10 u + 259 = 47910 u = 479 - 25910 u = 220
1 u = 220 ÷ 10 = 22 Number of coins that Fabian had at first
= 3 u ÷
12= 3 u x
21= 6 u = 6 x 22 = 132(b)Total number of coins that the three boys had at the end = 9 u = 9 x 22 = 198 Answer(s): (a) 132; (b) 198