Michael, Brandon and Sean had a total of 398 beads at first. After a week, the number of Michael's beads became 4 times the number of beads he had at first. The number of Brandon's beads decreased by 146. Sean had one-quarter as many beads as he had at first. In the end, the three boys had the same number of beads.
- How many beads did Sean have at first?
- What was the total number of beads that the three boys had in the end?
|
Michael |
Brandon |
Sean |
Total |
Before |
1 u |
4 u + 146 |
16 u |
|
Change |
x 4 |
- 146 |
x 14 |
|
After |
4 u |
4 u |
4 u |
12 u |
(a)
Total number of beads at first
=
1 u + 4 u + 146 + 16 u
= 21 u + 146
21 u + 146 = 39821 u = 398 - 14621 u = 252
1 u = 252 ÷ 21 = 12 Number of beads that Sean had at first
= 4 u ÷
14= 4 u x
41= 16 u = 16 x 12 = 192(b)Total number of beads that the three boys had at the end = 12 u = 12 x 12 = 144 Answer(s): (a) 192; (b) 144