Linda and Liam received $444 in total from their father. After Linda spent ²₃ of her money and Liam deposited ²₇ of his money into his savings account, Linda had twice as much money as Liam.

1. Find the amount of money Linda received from her father.
2. If Liam' savings increased by 20% after the deposit, how much was Liam' savings in the bank in the end?

	Linda	Liam	Total
Before	3x10 = 30 u	7 u	$444
Change	- 2x10 = - 20 u	- 2 u
After	1x10 = 10 u	5 u
Comparing Linda and Liam in the end	2x5	1x5

Fraction of Linda's money left
= 1 - ²₃
= ¹₃

Fraction of Liam's money left
= 1 - ²₇
= ⁵₇

The amount that Linda had in the end is repeated.  Make the amount that Linda had in the end the same. LM of 2 and 1 is 10.

Total amount given to Linda and Liam
= 30 u + 7 u
= 37 u

37 u = 444

1 u = 444 ÷ 37 = 12

Amount that Linda received from her father
= 30 u
= 30 x 12
= $360

(b)
Amount that Liam deposited
= 2 u
= 2 x 12
= $24

Savings that Liam had at first = 100%

Savings that Liam had in the end
= 100% + 20%
= 120%

20% of the savings = 24
1% of the savings = ²⁴₂₀
120% of the savings = 120 x ²⁴₂₀ = 144

Liam's savings in the end = $144

Answer(s): (a) $360; (b) $144