Jeremy has a carton containing some green kiwis and golden kiwis. If he adds in 14 green kiwis, 0.7 of the kiwis in the carton will be golden kiwis. If he adds in 59 golden kiwis, ⁶₇ of the kiwis in the carton will be green kiwis. How many kiwis are there in the carton?

	Golden kiwis	Green kiwis	Golden kiwis	Green kiwis
Before	7 u	3 u - 14	6 p - 59	1 p
Change		+ 14	+ 59
After	7 u	3 u	6 p	1 p

0.7 = ⁷₁₀ = ⁷₁₀

If he adds 14 green kiwis,
Number of green kiwis in the end
= 10 u - 7 u
= 3 u

If he adds 59 golden kiwis,
Number of green kiwis in the end
= 7 p - 6 p
= 1 p

The number of each type in both scenarios remain unchanged at first.

7 u = 6 p - 59 --- (1)

3 u - 14 = 1 p
3 u = 1 p + 14 --- (2)

Make u the same.
(1)_x3
21 u = 18 p - 177 --- (3)

(2)_x7
21 u = 7 p + 98 --- (4)

(3) = (4)
18 p - 177 = 7 p + 98
18 p - 7 p = 177 + 98
11 p = 275

1 p = 275 ÷ 11 = 25

Number of kiwis at first
= 1 p + 6 p - 59
= 7 p - 59
= 7 x 25 - 59
= 175 - 59
= 116

Answer(s): 116