Jeremy has a carton containing some green kiwis and golden kiwis. If he adds in 26 green kiwis, 0.6 of the kiwis in the carton will be golden kiwis. If he adds in 60 golden kiwis, ⁶₇ of the kiwis in the carton will be green kiwis. How many kiwis are there in the carton?

	Golden kiwis	Green kiwis	Golden kiwis	Green kiwis
Before	3 u	2 u - 26	6 p - 60	1 p
Change		+ 26	+ 60
After	3 u	2 u	6 p	1 p

0.6 = ⁶₁₀ = ³₅

If he adds 26 green kiwis,
Number of green kiwis in the end
= 5 u - 3 u
= 2 u

If he adds 60 golden kiwis,
Number of green kiwis in the end
= 7 p - 6 p
= 1 p

The number of each type in both scenarios remain unchanged at first.

3 u = 6 p - 60 --- (1)

2 u - 26 = 1 p
2 u = 1 p + 26 --- (2)

Make u the same.
(1)_x2
6 u = 12 p - 120 --- (3)

(2)_x3
6 u = 3 p + 78 --- (4)

(3) = (4)
12 p - 120 = 3 p + 78
12 p - 3 p = 120 + 78
9 p = 198

1 p = 198 ÷ 9 = 22

Number of kiwis at first
= 1 p + 6 p - 60
= 7 p - 60
= 7 x 22 - 60
= 154 - 60
= 94

Answer(s): 94