Jeremy has a carton containing some bunches of green grapes and bunches of red grapes. If he adds in 40 bunches of green grapes, 0.7 of the bunches of grapes in the carton will be bunches of red grapes. If he adds in 66 bunches of red grapes,
34 of the bunches of grapes in the carton will be green bunches of grapes. How many bunches of grapes are there in the carton?
|
Bunches of red grapes |
Bunches of green grapes |
Bunches of red grapes |
Bunches of green grapes |
Before |
7 u |
3 u - 40 |
3 p - 66 |
1 p |
Change |
|
+ 40 |
+ 66 |
|
After |
7 u |
3 u |
3 p |
1 p |
0.7 =
710 =
710If he adds 40 bunches of green grapes,
Number of bunches of green grapes in the end
= 10 u - 7 u
= 3 u
If he adds 66 bunches of red grapes,
Number of bunches of green grapes in the end
= 4 p - 3 p
= 1 p
The number of each type in both scenarios remain unchanged at first.
7 u = 3 p - 66 --- (1)
3 u - 40 = 1 p
3 u = 1 p + 40 --- (2)
Make u the same.
(1)
x3 21 u = 9 p - 198 --- (3)
(2)
x7 21 u = 7 p + 280 --- (4)
(3) = (4)
9 p - 198 = 7 p + 280
9 p - 7 p = 198 + 280
2 p = 478
1 p = 478 ÷ 2 = 239
Number of bunches of grapes at first
= 1 p + 3 p - 66
= 4 p - 66
= 4 x 239 - 66
= 956 - 66
= 890
Answer(s): 890