Jeremy has a carton containing some bunches of green grapes and bunches of purple grapes. If he adds in 25 bunches of green grapes, 0.7 of the bunches of grapes in the carton will be bunches of purple grapes. If he adds in 50 bunches of purple grapes,
45 of the bunches of grapes in the carton will be green bunches of grapes. How many bunches of grapes are there in the carton?
|
Bunches of purple grapes |
Bunches of green grapes |
Bunches of purple grapes |
Bunches of green grapes |
Before |
7 u |
3 u - 25 |
4 p - 50 |
1 p |
Change |
|
+ 25 |
+ 50 |
|
After |
7 u |
3 u |
4 p |
1 p |
0.7 =
710 =
710If he adds 25 bunches of green grapes,
Number of bunches of green grapes in the end
= 10 u - 7 u
= 3 u
If he adds 50 bunches of purple grapes,
Number of bunches of green grapes in the end
= 5 p - 4 p
= 1 p
The number of each type in both scenarios remain unchanged at first.
7 u = 4 p - 50 --- (1)
3 u - 25 = 1 p
3 u = 1 p + 25 --- (2)
Make u the same.
(1)
x3 21 u = 12 p - 150 --- (3)
(2)
x7 21 u = 7 p + 175 --- (4)
(3) = (4)
12 p - 150 = 7 p + 175
12 p - 7 p = 150 + 175
5 p = 325
1 p = 325 ÷ 5 = 65
Number of bunches of grapes at first
= 1 p + 4 p - 50
= 5 p - 50
= 5 x 65 - 50
= 325 - 50
= 275
Answer(s): 275