Jeremy has a carton containing some washington apples and fuji apples. If he adds in 21 washington apples, 0.6 of the apples in the carton will be fuji apples. If he adds in 61 fuji apples,
45 of the apples in the carton will be green apples. How many apples are there in the carton?
|
Fuji apples |
Washington apples |
Fuji apples |
Washington apples |
Before |
3 u |
2 u - 21 |
4 p - 61 |
1 p |
Change |
|
+ 21 |
+ 61 |
|
After |
3 u |
2 u |
4 p |
1 p |
0.6 =
610 =
35If he adds 21 washington apples,
Number of washington apples in the end
= 5 u - 3 u
= 2 u
If he adds 61 fuji apples,
Number of washington apples in the end
= 5 p - 4 p
= 1 p
The number of each type in both scenarios remain unchanged at first.
3 u = 4 p - 61 --- (1)
2 u - 21 = 1 p
2 u = 1 p + 21 --- (2)
Make u the same.
(1)
x2 6 u = 8 p - 122 --- (3)
(2)
x3 6 u = 3 p + 63 --- (4)
(3) = (4)
8 p - 122 = 3 p + 63
8 p - 3 p = 122 + 63
5 p = 185
1 p = 185 ÷ 5 = 37
Number of apples at first
= 1 p + 4 p - 61
= 5 p - 61
= 5 x 37 - 61
= 185 - 61
= 124
Answer(s): 124