Jeremy has a carton containing some golden kiwis and green kiwis. If he adds in 25 golden kiwis, 0.6 of the kiwis in the carton will be green kiwis. If he adds in 57 green kiwis, ⁶₇ of the kiwis in the carton will be green kiwis. How many kiwis are there in the carton?

	Green kiwis	Golden kiwis	Green kiwis	Golden kiwis
Before	3 u	2 u - 25	6 p - 57	1 p
Change		+ 25	+ 57
After	3 u	2 u	6 p	1 p

0.6 = ⁶₁₀ = ³₅

If he adds 25 golden kiwis,
Number of golden kiwis in the end
= 5 u - 3 u
= 2 u

If he adds 57 green kiwis,
Number of golden kiwis in the end
= 7 p - 6 p
= 1 p

The number of each type in both scenarios remain unchanged at first.

3 u = 6 p - 57 --- (1)

2 u - 25 = 1 p
2 u = 1 p + 25 --- (2)

Make u the same.
(1)_x2
6 u = 12 p - 114 --- (3)

(2)_x3
6 u = 3 p + 75 --- (4)

(3) = (4)
12 p - 114 = 3 p + 75
12 p - 3 p = 114 + 75
9 p = 189

1 p = 189 ÷ 9 = 21

Number of kiwis at first
= 1 p + 6 p - 57
= 7 p - 57
= 7 x 21 - 57
= 147 - 57
= 90

Answer(s): 90