Fiona bought some necklaces and rings for her friends. The price of each necklace was $4.30 while the price of each ring was $13.70. For every 5 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
13 of the number of rings bought. If Fiona paid a total of $856.40, how much more did she pay for the rings than the necklaces?
Rings |
Necklaces |
3x5 |
1x5 |
Bought |
Free |
Bought |
5x3 |
1x3 |
|
15 u |
3 u |
2 u |
|
Rings |
Necklaces |
|
Bought |
Free |
Bought |
Number |
15 u |
3 u |
2 u |
Value |
$13.70 |
0 |
$4.30 |
Total value |
205.5 u |
0 |
8.6 u |
The number of rings bought is the repeated identity. Make the number of rings bought the same. LCM of 3 and 5 is 15.
Cost of the bought rings
= 15 u x 13.70
= 205.5 u
Cost of the bought necklaces
= 2 u x 4.30
= 8.6 u
Total cost of the bought items
= 205.5 u + 8.6 u
= 214.1 u
214.1 u = 856.40
1 u = 856.40 ÷ 214.10 = 4
Amount that she paid more for the rings than the necklaces
= 205.5 u - 8.6 u
= 196.9 u
= 196.9 x 4
= $787.60
Answer(s): $787.60