Ivory bought some necklaces and bracelets for her friends. The price of each necklace was $4.90 while the price of each bracelet was $13.70. For every 8 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
13 of the number of bracelets bought. If Ivory paid a total of $2119.80, how much more did she pay for the bracelets than the necklaces?
Bracelets |
Necklaces |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Bracelets |
Necklaces |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$13.70 |
0 |
$4.90 |
Total value |
328.8 u |
0 |
24.5 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 3 and 8 is 24.
Cost of the bought bracelets
= 24 u x 13.70
= 328.8 u
Cost of the bought necklaces
= 5 u x 4.90
= 24.5 u
Total cost of the bought items
= 328.8 u + 24.5 u
= 353.3 u
353.3 u = 2119.80
1 u = 2119.80 ÷ 353.30 = 6
Amount that she paid more for the bracelets than the necklaces
= 328.8 u - 24.5 u
= 304.3 u
= 304.3 x 6
= $1825.80
Answer(s): $1825.80