Opal bought some bracelets and necklaces for her friends. The price of each bracelet was $4.80 while the price of each necklace was $14.70. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Opal paid a total of $1639.50, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$14.70 |
0 |
$4.80 |
Total value |
308.7 u |
0 |
19.2 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 7 is 21.
Cost of the bought necklaces
= 21 u x 14.70
= 308.7 u
Cost of the bought bracelets
= 4 u x 4.80
= 19.2 u
Total cost of the bought items
= 308.7 u + 19.2 u
= 327.9 u
327.9 u = 1639.50
1 u = 1639.50 ÷ 327.90 = 5
Amount that she paid more for the necklaces than the bracelets
= 308.7 u - 19.2 u
= 289.5 u
= 289.5 x 5
= $1447.50
Answer(s): $1447.50