Sabrina bought some rings and bracelets for her friends. The price of each ring was $2.60 while the price of each bracelet was $12.20. For every 7 bracelets bought, she was given one such ring for free. After receiving the free rings, the number of rings was
13 of the number of bracelets bought. If Sabrina paid a total of $3199.20, how much more did she pay for the bracelets than the rings?
Bracelets |
Rings |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Bracelets |
Rings |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$12.20 |
0 |
$2.60 |
Total value |
256.2 u |
0 |
10.4 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 3 and 7 is 21.
Cost of the bought bracelets
= 21 u x 12.20
= 256.2 u
Cost of the bought rings
= 4 u x 2.60
= 10.4 u
Total cost of the bought items
= 256.2 u + 10.4 u
= 266.6 u
266.6 u = 3199.20
1 u = 3199.20 ÷ 266.60 = 12
Amount that she paid more for the bracelets than the rings
= 256.2 u - 10.4 u
= 245.8 u
= 245.8 x 12
= $2949.60
Answer(s): $2949.60