Linda bought some bracelets and necklaces for her friends. The price of each bracelet was $2.40 while the price of each necklace was $14.90. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₅ of the number of necklaces bought. If Linda paid a total of $2105.20, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$14.90	0	$2.40
Total value	521.5 u	0	4.8 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 5 and 7 is 35.

Cost of the bought necklaces
= 35 u x 14.90
= 521.5 u

Cost of the bought bracelets
= 2 u x 2.40  
= 4.8 u

Total cost of the bought items
= 521.5 u + 4.8 u
= 526.3 u

526.3 u = 2105.20

1 u = 2105.20 ÷ 526.30 = 4

Amount that she paid more for the necklaces than the bracelets
= 521.5 u - 4.8 u 
= 516.7 u
= 516.7 x 4
= $2066.80

Answer(s): $2066.80