Roshel bought some necklaces and bracelets for her friends. The price of each necklace was $4.70 while the price of each bracelet was $14.70. For every 7 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
15 of the number of bracelets bought. If Roshel paid a total of $2095.60, how much more did she pay for the bracelets than the necklaces?
Bracelets |
Necklaces |
5x7 |
1x7 |
Bought |
Free |
Bought |
7x5 |
1x5 |
|
35 u |
5 u |
2 u |
|
Bracelets |
Necklaces |
|
Bought |
Free |
Bought |
Number |
35 u |
5 u |
2 u |
Value |
$14.70 |
0 |
$4.70 |
Total value |
514.5 u |
0 |
9.4 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 5 and 7 is 35.
Cost of the bought bracelets
= 35 u x 14.70
= 514.5 u
Cost of the bought necklaces
= 2 u x 4.70
= 9.4 u
Total cost of the bought items
= 514.5 u + 9.4 u
= 523.9 u
523.9 u = 2095.60
1 u = 2095.60 ÷ 523.90 = 4
Amount that she paid more for the bracelets than the necklaces
= 514.5 u - 9.4 u
= 505.1 u
= 505.1 x 4
= $2020.40
Answer(s): $2020.40