Eva bought some bracelets and necklaces for her friends. The price of each bracelet was $2.30 while the price of each necklace was $13.60. For every 8 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₃ of the number of necklaces bought. If Eva paid a total of $3041.10, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$13.60	0	$2.30
Total value	326.4 u	0	11.5 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 3 and 8 is 24.

Cost of the bought necklaces
= 24 u x 13.60
= 326.4 u

Cost of the bought bracelets
= 5 u x 2.30  
= 11.5 u

Total cost of the bought items
= 326.4 u + 11.5 u
= 337.9 u

337.9 u = 3041.10

1 u = 3041.10 ÷ 337.90 = 9

Amount that she paid more for the necklaces than the bracelets
= 326.4 u - 11.5 u 
= 314.9 u
= 314.9 x 9
= $2834.10

Answer(s): $2834.10