Usha bought some rings and necklaces for her friends. The price of each ring was $2.30 while the price of each necklace was $10.10. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₅ of the number of necklaces bought. If Usha paid a total of $1074.30, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Necklaces	Rings
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$10.10	0	$2.30
Total value	353.5 u	0	4.6 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 5 and 7 is 35.

Cost of the bought necklaces
= 35 u x 10.10
= 353.5 u

Cost of the bought rings
= 2 u x 2.30  
= 4.6 u

Total cost of the bought items
= 353.5 u + 4.6 u
= 358.1 u

358.1 u = 1074.30

1 u = 1074.30 ÷ 358.10 = 3

Amount that she paid more for the necklaces than the rings
= 353.5 u - 4.6 u 
= 348.9 u
= 348.9 x 3
= $1046.70

Answer(s): $1046.70