Shannon bought some rings and bracelets for her friends. The price of each ring was $2.80 while the price of each bracelet was $11.90. For every 7 bracelets bought, she was given one such ring for free. After receiving the free rings, the number of rings was
13 of the number of bracelets bought. If Shannon paid a total of $2872.10, how much more did she pay for the bracelets than the rings?
Bracelets |
Rings |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Bracelets |
Rings |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$11.90 |
0 |
$2.80 |
Total value |
249.9 u |
0 |
11.2 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 3 and 7 is 21.
Cost of the bought bracelets
= 21 u x 11.90
= 249.9 u
Cost of the bought rings
= 4 u x 2.80
= 11.2 u
Total cost of the bought items
= 249.9 u + 11.2 u
= 261.1 u
261.1 u = 2872.10
1 u = 2872.10 ÷ 261.10 = 11
Amount that she paid more for the bracelets than the rings
= 249.9 u - 11.2 u
= 238.7 u
= 238.7 x 11
= $2625.70
Answer(s): $2625.70