Jaslyn bought some necklaces and rings for her friends. The price of each necklace was $3.90 while the price of each ring was $11.10. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₄ of the number of rings bought. If Jaslyn paid a total of $2257.50, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Rings	Necklaces
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$11.10	0	$3.90
Total value	310.8 u	0	11.7 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 4 and 7 is 28.

Cost of the bought rings
= 28 u x 11.10
= 310.8 u

Cost of the bought necklaces
= 3 u x 3.90  
= 11.7 u

Total cost of the bought items
= 310.8 u + 11.7 u
= 322.5 u

322.5 u = 2257.50

1 u = 2257.50 ÷ 322.50 = 7

Amount that she paid more for the rings than the necklaces
= 310.8 u - 11.7 u 
= 299.1 u
= 299.1 x 7
= $2093.70

Answer(s): $2093.70