Joelle bought some rings and necklaces for her friends. The price of each ring was $4.50 while the price of each necklace was $13.80. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₄ of the number of necklaces bought. If Joelle paid a total of $4798.80, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Necklaces	Rings
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$13.80	0	$4.50
Total value	386.4 u	0	13.5 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 4 and 7 is 28.

Cost of the bought necklaces
= 28 u x 13.80
= 386.4 u

Cost of the bought rings
= 3 u x 4.50  
= 13.5 u

Total cost of the bought items
= 386.4 u + 13.5 u
= 399.9 u

399.9 u = 4798.80

1 u = 4798.80 ÷ 399.90 = 12

Amount that she paid more for the necklaces than the rings
= 386.4 u - 13.5 u 
= 372.9 u
= 372.9 x 12
= $4474.80

Answer(s): $4474.80