Eva bought some bracelets and necklaces for her friends. The price of each bracelet was $2.90 while the price of each necklace was $13.30. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₃ of the number of necklaces bought. If Eva paid a total of $2327.20, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
3x7	1x7
Bought	Free	Bought
7x3	1x3
21 u	3 u	4 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	21 u	3 u	4 u
Value	$13.30	0	$2.90
Total value	279.3 u	0	11.6 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 3 and 7 is 21.

Cost of the bought necklaces
= 21 u x 13.30
= 279.3 u

Cost of the bought bracelets
= 4 u x 2.90  
= 11.6 u

Total cost of the bought items
= 279.3 u + 11.6 u
= 290.9 u

290.9 u = 2327.20

1 u = 2327.20 ÷ 290.90 = 8

Amount that she paid more for the necklaces than the bracelets
= 279.3 u - 11.6 u 
= 267.7 u
= 267.7 x 8
= $2141.60

Answer(s): $2141.60