Tiffany bought some necklaces and rings for her friends. The price of each necklace was $2.70 while the price of each ring was $10.80. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₄ of the number of rings bought. If Tiffany paid a total of $2173.50, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Rings	Necklaces
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$10.80	0	$2.70
Total value	302.4 u	0	8.1 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 4 and 7 is 28.

Cost of the bought rings
= 28 u x 10.80
= 302.4 u

Cost of the bought necklaces
= 3 u x 2.70  
= 8.1 u

Total cost of the bought items
= 302.4 u + 8.1 u
= 310.5 u

310.5 u = 2173.50

1 u = 2173.50 ÷ 310.50 = 7

Amount that she paid more for the rings than the necklaces
= 302.4 u - 8.1 u 
= 294.3 u
= 294.3 x 7
= $2060.10

Answer(s): $2060.10