Tammy bought some rings and necklaces for her friends. The price of each ring was $4.10 while the price of each necklace was $12.50. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was
13 of the number of necklaces bought. If Tammy paid a total of $1394.50, how much more did she pay for the necklaces than the rings?
Necklaces |
Rings |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Necklaces |
Rings |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$12.50 |
0 |
$4.10 |
Total value |
262.5 u |
0 |
16.4 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 7 is 21.
Cost of the bought necklaces
= 21 u x 12.50
= 262.5 u
Cost of the bought rings
= 4 u x 4.10
= 16.4 u
Total cost of the bought items
= 262.5 u + 16.4 u
= 278.9 u
278.9 u = 1394.50
1 u = 1394.50 ÷ 278.90 = 5
Amount that she paid more for the necklaces than the rings
= 262.5 u - 16.4 u
= 246.1 u
= 246.1 x 5
= $1230.50
Answer(s): $1230.50