Tiffany bought some bracelets and rings for her friends. The price of each bracelet was $2.50 while the price of each ring was $14.70. For every 8 rings bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₃ of the number of rings bought. If Tiffany paid a total of $3287.70, how much more did she pay for the rings than the bracelets?

Rings	Bracelets
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Rings	Bracelets
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$14.70	0	$2.50
Total value	352.8 u	0	12.5 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 3 and 8 is 24.

Cost of the bought rings
= 24 u x 14.70
= 352.8 u

Cost of the bought bracelets
= 5 u x 2.50  
= 12.5 u

Total cost of the bought items
= 352.8 u + 12.5 u
= 365.3 u

365.3 u = 3287.70

1 u = 3287.70 ÷ 365.30 = 9

Amount that she paid more for the rings than the bracelets
= 352.8 u - 12.5 u 
= 340.3 u
= 340.3 x 9
= $3062.70

Answer(s): $3062.70