Raeann bought some necklaces and bracelets for her friends. The price of each necklace was $3.60 while the price of each bracelet was $10.80. For every 7 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₄ of the number of bracelets bought. If Raeann paid a total of $939.60, how much more did she pay for the bracelets than the necklaces?

Bracelets	Necklaces
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Bracelets	Necklaces
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$10.80	0	$3.60
Total value	302.4 u	0	10.8 u

The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same.  LCM of 4 and 7 is 28.

Cost of the bought bracelets
= 28 u x 10.80
= 302.4 u

Cost of the bought necklaces
= 3 u x 3.60  
= 10.8 u

Total cost of the bought items
= 302.4 u + 10.8 u
= 313.2 u

313.2 u = 939.60

1 u = 939.60 ÷ 313.20 = 3

Amount that she paid more for the bracelets than the necklaces
= 302.4 u - 10.8 u 
= 291.6 u
= 291.6 x 3
= $874.80

Answer(s): $874.80