Emma bought some necklaces and rings for her friends. The price of each necklace was $4.90 while the price of each ring was $14.60. For every 8 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of rings bought. If Emma paid a total of $1499.60, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
3x8	1x8
Bought	Free	Bought
8x3	1x3
24 u	3 u	5 u

	Rings	Necklaces
	Bought	Free	Bought
Number	24 u	3 u	5 u
Value	$14.60	0	$4.90
Total value	350.4 u	0	24.5 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 3 and 8 is 24.

Cost of the bought rings
= 24 u x 14.60
= 350.4 u

Cost of the bought necklaces
= 5 u x 4.90  
= 24.5 u

Total cost of the bought items
= 350.4 u + 24.5 u
= 374.9 u

374.9 u = 1499.60

1 u = 1499.60 ÷ 374.90 = 4

Amount that she paid more for the rings than the necklaces
= 350.4 u - 24.5 u 
= 325.9 u
= 325.9 x 4
= $1303.60

Answer(s): $1303.60