Nicole bought some bracelets and necklaces for her friends. The price of each bracelet was $3.30 while the price of each necklace was $10.30. For every 8 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Nicole paid a total of $2900.70, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$10.30 |
0 |
$3.30 |
Total value |
247.2 u |
0 |
16.5 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 8 is 24.
Cost of the bought necklaces
= 24 u x 10.30
= 247.2 u
Cost of the bought bracelets
= 5 u x 3.30
= 16.5 u
Total cost of the bought items
= 247.2 u + 16.5 u
= 263.7 u
263.7 u = 2900.70
1 u = 2900.70 ÷ 263.70 = 11
Amount that she paid more for the necklaces than the bracelets
= 247.2 u - 16.5 u
= 230.7 u
= 230.7 x 11
= $2537.70
Answer(s): $2537.70