Sarah bought some bracelets and necklaces for her friends. The price of each bracelet was $2.20 while the price of each necklace was $10.10. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
13 of the number of necklaces bought. If Sarah paid a total of $662.70, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
3x7 |
1x7 |
Bought |
Free |
Bought |
7x3 |
1x3 |
|
21 u |
3 u |
4 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
21 u |
3 u |
4 u |
Value |
$10.10 |
0 |
$2.20 |
Total value |
212.1 u |
0 |
8.8 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 7 is 21.
Cost of the bought necklaces
= 21 u x 10.10
= 212.1 u
Cost of the bought bracelets
= 4 u x 2.20
= 8.8 u
Total cost of the bought items
= 212.1 u + 8.8 u
= 220.9 u
220.9 u = 662.70
1 u = 662.70 ÷ 220.90 = 3
Amount that she paid more for the necklaces than the bracelets
= 212.1 u - 8.8 u
= 203.3 u
= 203.3 x 3
= $609.90
Answer(s): $609.90