Kimberly bought some necklaces and bracelets for her friends. The price of each necklace was $3.90 while the price of each bracelet was $13.70. For every 5 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of bracelets bought. If Kimberly paid a total of $639.90, how much more did she pay for the bracelets than the necklaces?

Bracelets	Necklaces
3x5	1x5
Bought	Free	Bought
5x3	1x3
15 u	3 u	2 u

	Bracelets	Necklaces
	Bought	Free	Bought
Number	15 u	3 u	2 u
Value	$13.70	0	$3.90
Total value	205.5 u	0	7.8 u

The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same.  LCM of 3 and 5 is 15.

Cost of the bought bracelets
= 15 u x 13.70
= 205.5 u

Cost of the bought necklaces
= 2 u x 3.90  
= 7.8 u

Total cost of the bought items
= 205.5 u + 7.8 u
= 213.3 u

213.3 u = 639.90

1 u = 639.90 ÷ 213.30 = 3

Amount that she paid more for the bracelets than the necklaces
= 205.5 u - 7.8 u 
= 197.7 u
= 197.7 x 3
= $593.10

Answer(s): $593.10