Opal bought some necklaces and bracelets for her friends. The price of each necklace was $2.80 while the price of each bracelet was $10.60. For every 7 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₃ of the number of bracelets bought. If Opal paid a total of $2104.20, how much more did she pay for the bracelets than the necklaces?

Bracelets	Necklaces
3x7	1x7
Bought	Free	Bought
7x3	1x3
21 u	3 u	4 u

	Bracelets	Necklaces
	Bought	Free	Bought
Number	21 u	3 u	4 u
Value	$10.60	0	$2.80
Total value	222.6 u	0	11.2 u

The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same.  LCM of 3 and 7 is 21.

Cost of the bought bracelets
= 21 u x 10.60
= 222.6 u

Cost of the bought necklaces
= 4 u x 2.80  
= 11.2 u

Total cost of the bought items
= 222.6 u + 11.2 u
= 233.8 u

233.8 u = 2104.20

1 u = 2104.20 ÷ 233.80 = 9

Amount that she paid more for the bracelets than the necklaces
= 222.6 u - 11.2 u 
= 211.4 u
= 211.4 x 9
= $1902.60

Answer(s): $1902.60