Lynn bought some necklaces and bracelets for her friends. The price of each necklace was $2.50 while the price of each bracelet was $14.80. For every 8 bracelets bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was
13 of the number of bracelets bought. If Lynn paid a total of $2206.20, how much more did she pay for the bracelets than the necklaces?
Bracelets |
Necklaces |
3x8 |
1x8 |
Bought |
Free |
Bought |
8x3 |
1x3 |
|
24 u |
3 u |
5 u |
|
Bracelets |
Necklaces |
|
Bought |
Free |
Bought |
Number |
24 u |
3 u |
5 u |
Value |
$14.80 |
0 |
$2.50 |
Total value |
355.2 u |
0 |
12.5 u |
The number of bracelets bought is the repeated identity. Make the number of bracelets bought the same. LCM of 3 and 8 is 24.
Cost of the bought bracelets
= 24 u x 14.80
= 355.2 u
Cost of the bought necklaces
= 5 u x 2.50
= 12.5 u
Total cost of the bought items
= 355.2 u + 12.5 u
= 367.7 u
367.7 u = 2206.20
1 u = 2206.20 ÷ 367.70 = 6
Amount that she paid more for the bracelets than the necklaces
= 355.2 u - 12.5 u
= 342.7 u
= 342.7 x 6
= $2056.20
Answer(s): $2056.20