Ivory bought some rings and necklaces for her friends. The price of each ring was $4.40 while the price of each necklace was $11.90. For every 5 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was
13 of the number of necklaces bought. If Ivory paid a total of $936.50, how much more did she pay for the necklaces than the rings?
Necklaces |
Rings |
3x5 |
1x5 |
Bought |
Free |
Bought |
5x3 |
1x3 |
|
15 u |
3 u |
2 u |
|
Necklaces |
Rings |
|
Bought |
Free |
Bought |
Number |
15 u |
3 u |
2 u |
Value |
$11.90 |
0 |
$4.40 |
Total value |
178.5 u |
0 |
8.8 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 3 and 5 is 15.
Cost of the bought necklaces
= 15 u x 11.90
= 178.5 u
Cost of the bought rings
= 2 u x 4.40
= 8.8 u
Total cost of the bought items
= 178.5 u + 8.8 u
= 187.3 u
187.3 u = 936.50
1 u = 936.50 ÷ 187.30 = 5
Amount that she paid more for the necklaces than the rings
= 178.5 u - 8.8 u
= 169.7 u
= 169.7 x 5
= $848.50
Answer(s): $848.50