Tammy bought some rings and necklaces for her friends. The price of each ring was $3.20 while the price of each necklace was $12.10. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₅ of the number of necklaces bought. If Tammy paid a total of $3009.30, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Necklaces	Rings
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$12.10	0	$3.20
Total value	423.5 u	0	6.4 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 5 and 7 is 35.

Cost of the bought necklaces
= 35 u x 12.10
= 423.5 u

Cost of the bought rings
= 2 u x 3.20  
= 6.4 u

Total cost of the bought items
= 423.5 u + 6.4 u
= 429.9 u

429.9 u = 3009.30

1 u = 3009.30 ÷ 429.90 = 7

Amount that she paid more for the necklaces than the rings
= 423.5 u - 6.4 u 
= 417.1 u
= 417.1 x 7
= $2919.70

Answer(s): $2919.70