Cathy bought some rings and necklaces for her friends. The price of each ring was $2.90 while the price of each necklace was $10.10. For every 7 necklaces bought, she was given one such ring for free. After receiving the free rings, the number of rings was ¹₄ of the number of necklaces bought. If Cathy paid a total of $2040.50, how much more did she pay for the necklaces than the rings?

Necklaces	Rings
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Necklaces	Rings
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$10.10	0	$2.90
Total value	282.8 u	0	8.7 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 4 and 7 is 28.

Cost of the bought necklaces
= 28 u x 10.10
= 282.8 u

Cost of the bought rings
= 3 u x 2.90  
= 8.7 u

Total cost of the bought items
= 282.8 u + 8.7 u
= 291.5 u

291.5 u = 2040.50

1 u = 2040.50 ÷ 291.50 = 7

Amount that she paid more for the necklaces than the rings
= 282.8 u - 8.7 u 
= 274.1 u
= 274.1 x 7
= $1918.70

Answer(s): $1918.70