Joelle bought some bracelets and necklaces for her friends. The price of each bracelet was $4.70 while the price of each necklace was $14.80. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was ¹₄ of the number of necklaces bought. If Joelle paid a total of $2999.50, how much more did she pay for the necklaces than the bracelets?

Necklaces	Bracelets
4x7	1x7
Bought	Free	Bought
7x4	1x4
28 u	4 u	3 u

	Necklaces	Bracelets
	Bought	Free	Bought
Number	28 u	4 u	3 u
Value	$14.80	0	$4.70
Total value	414.4 u	0	14.1 u

The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same.  LCM of 4 and 7 is 28.

Cost of the bought necklaces
= 28 u x 14.80
= 414.4 u

Cost of the bought bracelets
= 3 u x 4.70  
= 14.1 u

Total cost of the bought items
= 414.4 u + 14.1 u
= 428.5 u

428.5 u = 2999.50

1 u = 2999.50 ÷ 428.50 = 7

Amount that she paid more for the necklaces than the bracelets
= 414.4 u - 14.1 u 
= 400.3 u
= 400.3 x 7
= $2802.10

Answer(s): $2802.10