Kimberly bought some necklaces and rings for her friends. The price of each necklace was $2.10 while the price of each ring was $10.90. For every 7 rings bought, she was given one such necklace for free. After receiving the free necklaces, the number of necklaces was ¹₅ of the number of rings bought. If Kimberly paid a total of $3471.30, how much more did she pay for the rings than the necklaces?

Rings	Necklaces
5x7	1x7
Bought	Free	Bought
7x5	1x5
35 u	5 u	2 u

	Rings	Necklaces
	Bought	Free	Bought
Number	35 u	5 u	2 u
Value	$10.90	0	$2.10
Total value	381.5 u	0	4.2 u

The number of rings bought is the repeated identity. Make the number of rings bought the same.  LCM of 5 and 7 is 35.

Cost of the bought rings
= 35 u x 10.90
= 381.5 u

Cost of the bought necklaces
= 2 u x 2.10  
= 4.2 u

Total cost of the bought items
= 381.5 u + 4.2 u
= 385.7 u

385.7 u = 3471.30

1 u = 3471.30 ÷ 385.70 = 9

Amount that she paid more for the rings than the necklaces
= 381.5 u - 4.2 u 
= 377.3 u
= 377.3 x 9
= $3395.70

Answer(s): $3395.70