Cathy bought some bracelets and necklaces for her friends. The price of each bracelet was $2.60 while the price of each necklace was $14.20. For every 7 necklaces bought, she was given one such bracelet for free. After receiving the free bracelets, the number of bracelets was
14 of the number of necklaces bought. If Cathy paid a total of $1216.20, how much more did she pay for the necklaces than the bracelets?
Necklaces |
Bracelets |
4x7 |
1x7 |
Bought |
Free |
Bought |
7x4 |
1x4 |
|
28 u |
4 u |
3 u |
|
Necklaces |
Bracelets |
|
Bought |
Free |
Bought |
Number |
28 u |
4 u |
3 u |
Value |
$14.20 |
0 |
$2.60 |
Total value |
397.6 u |
0 |
7.8 u |
The number of necklaces bought is the repeated identity. Make the number of necklaces bought the same. LCM of 4 and 7 is 28.
Cost of the bought necklaces
= 28 u x 14.20
= 397.6 u
Cost of the bought bracelets
= 3 u x 2.60
= 7.8 u
Total cost of the bought items
= 397.6 u + 7.8 u
= 405.4 u
405.4 u = 1216.20
1 u = 1216.20 ÷ 405.40 = 3
Amount that she paid more for the necklaces than the bracelets
= 397.6 u - 7.8 u
= 389.8 u
= 389.8 x 3
= $1169.40
Answer(s): $1169.40